Math, asked by bluesoul, 9 months ago

2. A, B and C can do a piece of work in 12 days, 15 days and 10 days respectively. In what time will
they all together finish it?​

Answers

Answered by BrainlyConqueror0901
41

Answer:

\huge{\pink{\green{\sf{\therefore Time\:taken=4\:days}}}}

Step-by-step explanation:

\huge{\pink{\green{\underline{\red{\sf{SOLUTION-}}}}}}

• In the given question information given about 3 people and their completion of time to do the work is given.

• So, we have to find the time taken to do the same work if they work together.

 \underline \bold{Given : } \\  \implies A\: can \: do \: a  \:  work \:  = 12 \: days  \\  \implies B\: can \: do \: same \: work = 15 \: days \\  \implies C \:do \: the \: same \: work = 10  \: days \\  \\  \underline \bold{To \: Find : } \\  \implies Time \: taken \: if \: they \: work \: together =  ?

• According to given question :

 \bold{For \: A}  \\ \implies Work \: do \: in \: one \: day =  \frac{1}{12}  -  -  -  -  (1) \\  \\   \bold{For \: B}\\  \implies  Work \: do \: in \: one \: day =  \frac{1}{15} -  -  -  - (2) \\  \\ \bold{ For \: C} \\   \implies Work \:do \: in \: one \: day =  \frac{1}{10} -  -  -  - (3)  \\  \\ \bold{  If \: they \: work \: together } \\   \bold {Adding \: (1)(2) \: and \: (3)} \\  \implies  \frac{1}{12}  +  \frac{1}{15}  +  \frac{1}{10}  \\ \bold {Take \: Lcm \: of \: 12,15\:  and \: 10 = 60}\\  \implies  \frac{5 + 4 + 6}{60}  \\  \implies  \frac{15}{60}  \\  \implies  \frac{60}{15}  \\   \bold{\implies 4 \: days} \\  \\   \bold{\therefore In \: 4 \:days \: they \: complete \: the \: work}

Answered by Anonymous
36

A fo a piece of work in 12 days.

So,

Work done by A in 1 day = \dfrac{1}{12} days ____ (eq 1)

Similarly,

B do a piece of work in 15 days.

Work done by B in 1 day = \dfrac{1}{15} days ____ (eq 2)

C do a piece of work in 10 days.

Work done by C in 1 day = \dfrac{1}{10} days _____ (eq 3)

We have to find that in how many days A, B and C all together to finish the work.

We have to simply add (eq 1), (eq 2) and (eq 3)

=> \dfrac{1}{12}\:+\:\dfrac{1}{15}\:+\:\dfrac{1}{10}

=> \dfrac{5\:+\:4\:+\:6}{60}

=> \dfrac{15}{60}

=> \dfrac{1}{4}

=> 4 days

In 4 days A, B and C will finish the work all together.

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