Question

2. A bag contains 2 white balls, 3 black balls and 4 red balls. In how many ways can 3 balls be drawn from the bag, if at least one black ball is to be included in the draw
A. 64
B. 128
C. 132
D. 222
​

Answer 1

All black+2black*1 others+1black*2 others

=3c3+3c2*6c1+3c1*6c2

=1+3*6+3*15

=64

solved by: Magic of Math(MOM)

www.facebook.com/groups/mom.19/

Answer 2

Answer:

64

Step-by-step explanation:

From 2 white balls, 3 black balls and 4 red balls, 3 balls are to be selected such that

at least one black ball should be there.

Hence we have 3 choices

All three are black

Two are black and one is non black

One is black and two are non black

Total number of ways

= 3C3 + (3C2 x 6C1) + (3C1 x 6C2) [because 6 are non black]

=1+[3×6] + [3 × (6×52×1)] = 1+18+45 = 64