Question

2. A bag contains 5 yellow, 6 blue, 2 purple, and 7 red marbles.
i). what is the probability of choosing a blue marble.
ii). A yellow marbles is drawn and then a red marble is drawn. Neither is replaced. What is the
probability of drawing a yellow marble on the third draw?​

Answer 1

Answer:

i)30%

ii)27.78%

Step-by-step explanation:

i)((100/(sum of all marbles))×no. of blue marbles)%

=((100/5+6+2+7))*6)%

=((100/20)*6)%

=(5*6)%

=30%

ii)((100/((sum of all marbles)-2))*no. of yellow marbles)% ('-2' because 2 marbles are removed )

=((100/((5+6+2+7)-2))* 5)%

=((100/(20-2)* 5)%

=((100/18)*5)%

=(5.5555555556*5)%

=27.777777778%

Please mark brainliest answer cause I did it from my tab and typing is too hard