Question

2: A bag contains a red ball, a blue ball and a yellow ball, all the balls being of the same size. Kritika takes out a ball from the bag without looking into it. What is the probability that she takes out the
(i) yellow ball?
(ii) red ball?
(iii) blue ball?​

Answer 1

Step-by-step explanation:

no of red balls - 1

no of blue balls- 1

no of yellow balls - 1

chances of getting a yellow ball = total no of outcomes/ total no of chances

= 3/3= 1

chances of getting a blue ball is 3/3 = 1

chances of getting a red ball is 3/3 =1

Answer 2

Step-by-step explanation:

Kritika takes out a ball from the bag without looking into it. So, it is equally likely that she takes out any one of them from the bag.

Let Y be the event ‘the ball taken out is yellow’, B be the event ‘the ball taken out is blue’, and R be the event ‘the ball taken out is red’.

The number of possible outcomes = Number of balls in the bag = n(S) = 3.

(i) The number of outcomes favourable to the event Y = n(Y) = 1.

So, P(Y) = n(Y)/n(S) =1/3

Similarly, (ii) P(R) = 1/3

(iii) P(B) = ⅓

Hope it helps.........