2: A bag contains a red ball, a blue ball and a yellow ball, all the balls being of the same size. Kritika takes out a ball from the bag without looking into it. What is the probability that she takes out the
(i) yellow ball?
(ii) red ball?
(iii) blue ball?
Answers
Step-by-step explanation:
no of red balls - 1
no of blue balls- 1
no of yellow balls - 1
chances of getting a yellow ball = total no of outcomes/ total no of chances
= 3/3= 1
chances of getting a blue ball is 3/3 = 1
chances of getting a red ball is 3/3 =1
Step-by-step explanation:
Kritika takes out a ball from the bag without looking into it. So, it is equally likely that she takes out any one of them from the bag.
Let Y be the event ‘the ball taken out is yellow’, B be the event ‘the ball taken out is blue’, and R be the event ‘the ball taken out is red’.
The number of possible outcomes = Number of balls in the bag = n(S) = 3.
(i) The number of outcomes favourable to the event Y = n(Y) = 1.
So, P(Y) = n(Y)/n(S) =1/3
Similarly, (ii) P(R) = 1/3
(iii) P(B) = ⅓
Hope it helps.........