Question

2. A bag contains a total at 105 coins of Re. 1, 50 paise and 25 paise denominations. Find the total number of coins of Re. 1 if there are a total of 50.50 rupees in the bag and it is known that the number of 25 paise coins is 133.33% more than the number of Re. 1 coins.

Answer 1

Answer:

24

Step-by-step explanation:

let say 1 rs Coins  = 3x

Then 25 Paise coins = 3x  + 3x(133.33/100)  = 7x

50 Paise coins = 105 - 3x - 7x = 105 - 10x

Value of 1 rs coins = 3x  Rs

Value of 25 Paise coins = (25/100) * 7x =  1.75x  Rs

Value of 50 Paise coins = (50/100) * (105-10x)  = 52.5 - 5x  Rs

Total Value = 3x + 1.75x + 52.5 - 5x  = 52.5 - 0.25x

52.5 - 0.25x = 50.5

=> 0.25x = 2

=> x = 8

1 Rs coins = 3x = 3 * 8 = 24

Number of 1 Rs coins = 24