2. A bag contains few black and red marbles. The number of red marbles are two more than
half the black marbles. If total number of marbles are 14. Then find the probability of a black
and a red marbles in a draw of a single marble.
Attachments:
Answers
Answered by
1
Answer:
Probability of getting black marble =6/14=3/7
Probability of getting red marble=8/14=4/7
Answered by
3
Answer:
Step-by-step explanation:
let black marbles be x and red be y
y =2+1/2x
2y=4+x
-4=x-2y.......1
x+y= 14.........2( multiply by 2)
1 and 2,
2x+2y=28
x-2y=-4
3x= 24
x=8
y=6
p(x)=8/14=4/7
p(y)=6/14= 3/7
Similar questions