Question

2. A bag contains n balls numbered from 1 to n, with n > 2. There are n x (n - 1)
ways in which Julio can remove one ball from the bag and then remove a second ball.
This is because there are n possible choices for the first ball and then n 1 possible
choices for the second ball. For example, when a bag contains 6 balls numbered from
1 to 6, 4 of which are black and 2 of which are gold, there are 6 x 5 = 30 ways in
which he can remove two balls in this way, and 4 x3 12 ways in which both balls
are black.
(a) A bag contains 11 balls numbered from 1 to 11, 7 of which are black and 4
of which are gold. Julio removes two balls as described above. What is the
probability that both balls are black?
(b) For some integer g 22, a second bag contains 6 black balls and 9 gold balls:
the balls are numbered from 1 to g +6. Julio removes two balls as described
above. The probability that both balls are black is g. Determine the value of g.
() For some integer 1 2 2. a third bag contains 2x black balls and a gold balls; the
balls are numbered from 1 to 3. Julio removes two balls as described above,
The probability that both balls are black is T. Determine the value of r.
(a) For some integer r3, a fourth bag contains 10 black balls, 18 gold balls, and
r red balls: the balls are numbered from 1 to r + 28. This time, Julio draws
three balls one after another. The probability that two of these three balls are
black and one of these three balls is gold is at least What is the largest
possible value or ?
1/
3000​

Answer 1

Answer:

sorry bro itni jada English nhi aati mere ko