Question

2
A ball is projected at angle 60° from horizontal with
speed 10 m/s. There is a horizontal mirror on the
ground. After how much time the velocity of the ball
will be perpendicular to the velocity of its image?
60
(1)
√3-1
2
(2)
VO
S.
2
(3)
√3-1
√3+1
S
(4)
S​

Answer 1

Answer:

a ball is projected at angle 60

speed = 10m/s

uy= 10 sin 60

ux= 10 cos 60

the angle b/w ball and image is 90

the angle b/w ball and mirror

tan 45= vy\vx

1= uy-gt/ux

10 cos 60 = 10sin -9.8

9.8=5√3-5

t= 3.66/9.8=0.37