Question

2. A ball is projected vertically up with a speed of 50 m/s. Find the maximum height,
the time to reach the maximum height, and the speed at the maximum height
(g=10 m/s) (AS) (Ans: 125m; 5s, zero)
ith their centers 10 cm apart.​

Answer 1

Given

• A ball is projected vertically
• Initial Velocity = 50 m/s

To Find

• Maximum height reached
• Time taken
• The velocity of the ball at its maximum height

Solution

● v²-u² = 2gs

● v = u + gt

✭ Maximum Height Reached :

→ v²-u² = 2gs

→ 0²-50² = 2 × (-10) × s

→ -2500 = -20s

→ -2500/-20 = s

→ Maximum Height = 125 m

━━━━━━━━━━━━━━━━━━━━

✭ Time taken :

→ v = u + gt

→ 0 = 50 + (-10) × t

→ -50 = -10t

→ -50/-10 = t

→ Time = 5 sec

• Also the Velocity of the ball at its maximum height would be zero. This is because, of it had any other Velocity except 0 then it would cover some more distance.