Question

2. A ball is thrown up with a speed of 15 m/s. How
high will it go before it begins to fall?
(2)
(g= 9.8m/s.s)​

Answer 1

• Answer. It will travel height of 11.48 m before it begins to fall.....

Answer 2

Answer:

Final speed at the top most point (v) = 0

Initial speed (u) = 15 m/s

a = -g = -9.8

Hence, as per the third law of motion,/

v square = u square + 2.a.s

or distance s = (v square - u square)/2.a

or s = (0 - 225)/(2 x -9.8)

or s = 225/19.6 = 11.48 mtrs Answer

Explanation:

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