2. A ball when thrown vertically upwards reaches a maxim
height of 19.6 m. Find the velocity with which this ball was
thrown to reach this height and the time taken by it.
Answers
Answered by
2
Answer:
19.79m/s speed ,time = 1.979s
Explanation:
at s =19.6m v =0
v^2=u^2 +2as
therefore 0=u^2 + 2gs
0=u^2 -20×19.6
u= (392)^1/2
u=19.79m/s
0= u+ at 0=19.79 -10t t=1.979s
Answered by
0
Answer:
i dont know
Explanation:
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