Question

2. A ball when thrown vertically upwards reaches a maxim
height of 19.6 m. Find the velocity with which this ball was
thrown to reach this height and the time taken by it.​

Answer 1

Answer:

19.79m/s speed ,time = 1.979s

Explanation:

at s =19.6m v =0

v^2=u^2 +2as

therefore 0=u^2 + 2gs

0=u^2 -20×19.6

u= (392)^1/2

u=19.79m/s

0= u+ at 0=19.79 -10t t=1.979s

Answer 2

Answer:

i dont know

Explanation: