Question

2) A beaker contains water up to the height of 0.2 m. if the density of water is 1000 kg/m^3 and acceleration due to gravity is 9.8 m/s^2, calculate the pressure exerted by water at the bottom of the beaker.

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Answer 1

The pressure= 1.47×104 N m−2

B

The trust at the base level=147 N

Explanation:

Pressure =ρgh

where ρ=density of water

g=acceleration due to gravity

P=103×9.8×1.5=1.47×104Nm2

Upthrust = Force exerted = Pressure \times Area

⇒Upthrust=1.47×104Nm2×100×10−4m=147N