Question

2. A block is dragged on smooth plane with the help of a
rope which moves with velocity v. The horizontal
velocity of the block is
a) v
b) v/sin theta
c)v sin theta
d)v/ cos theta​

Answer 1

Answer:

A block is dragged on smooth plane with the help of a

rope which moves with velocity v. The horizontal

velocity of the block is

Answer 2

Explanation:

Horizontal component of velocity along the velocity of the rope should be same,

$\rm v_m sin \: θ= v$

$\rm v_m = \dfrac{v}{sin\: θ }$

So, the correct answer is $\rm (b) \: \dfrac{v}{sin \: θ }$