Question

2. A block of mass 1 kg is thrown from the surface of the earth with the speed of 10 m/s. Find the work done by the gravitational force during vertical motion of the body. (g = 10 m/s)
Ans. -50J​

Answer 1

Answer:

$\large{\bf{\underline{\underline{GIVEN:-}}}}$

Mass (m) = 1 kg.

velocity (v) = 10ms⁻¹.

Acceleration due to gravity (g) = 10ms⁻².

$\large{\bf{\underline{\underline{TO:FIND:-}}}}$

Work done by the gravitational force.

$\large{\bf{\underline{\underline{SOLUTION:-}}}}$

We know that work done during vertical motion, i.e., kinetic energy is:

$\sf \implies {\red{K.E.=\dfrac{1}{2} mv^2}}$

$\sf \implies K.E. = \dfrac{1}{2} \times 1 \times 10^2$

$\sf \implies K.E.=\dfrac{100}{2}$

$\implies \boxed{\sf{\red{ K.E. = 50 J.}}}$

WORK DONE :- 50 J.

Answer 2

Answer:

Question:-

A block of mass 1 kg is thrown from the surface of the earth with the speed of 10 m/s. Find the work done by the gravitational force during vertical motion of the body. (g = 10 m/s)

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$\LARGE{\bf{\underline{\underline{GIVEN:-}}}}$

Mass (m) = 1 kg.

velocity (v) = 10ms⁻¹.

Acceleration due to gravity (g) = 10ms⁻².

$\LARGE{\bf{\underline{\underline{TO:FIND:-}}}}$

Work done by the gravitational force.

$\LARGE{\bf{\underline{\underline{SOLUTION:-}}}}$

We know that work done during vertical motion, i.e., kinetic energy is:

$\sf{\red{K.E.=\dfrac{1}{2} mv^2}}$

$\sf K.E. = \dfrac{1}{2} \times 1 \times 10^2$

$\sf K.E.=\dfrac{100}{2}$

$\boxed{\sf{\red{ K.E. = 50 J.}}}$

WORK DONE :- 50 J.

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