Question

2. A body is falling freely under gravity. How much distance it falls during an interval of time between 1st and 2nd seconds of its motion, taking g=10?

Answer 1

Answer:

Motion

Explanation:

S = ut + $\frac{1}{2} gt^{2}$

Here, Initial velocity u = 0 m/s and

          gravity g = 10  m/s^2

Total distance covered in two seconds -

$S_{2}$ = ut + $\frac{1}{2} gt^{2}$                 ( t = 2 seconds)

$S_{2}$ =| 0 * 2 +  $\frac{1}{2} .(10).2^{2}$ |

   = 0 * + $\frac{40}{2}$

   = 20 m

Total distance covered in one second -

$S_{1}$= ut + $\frac{1}{2} gt^{2}$          ( t= 1 second)

$S_{1}$ =| 0 * 2 +  $\frac{1}{2} .(10).1^{2}$ |

   = 0 * + $\frac{10}{2}$

   = 5 m

=> Distance covered by body during an interval of time between first and second seconds of its motion = ( $S_{2} - S_{1}$) = 20–5 = 15m .