Question

2.
A body moves with uniform velocity of u = 7 m
s from t = 0 to t = 1.5 sec. For t > 1.5 sec, i
starts moving with an acceleration of 10 m/s?. The
distance between t = 0 to t = 3 sec. will be-
[1] 47.75 m
[2] 32.25 m.
[3] 16.75 m.
[4] 27.50 m.
​

Answer 1

Explanation:

ANSWER

• Distance covered in first 1.5 sec =ut=1.5×7=10.5m
• Distance covered in last 1.5 sec =ut+

2

1

×10×t

2

=1.5×7+5×2.25=10.5+11.25=21.75m

Total distance =10.5+21.75=32.25m

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