Question

2. A body of mass 5 kg is placed at the origin and can only move a s
x-axis. A force of 10 N acts on it in a direction making an angle of 60 with
the x-axis. If it is displaced along the x-axis by 4 metres, the work done by
the force is​

Answer 1

20joule

Explanation:

Questions

A boy of mass 5 kg is placed at at the origin and can only move x axis.

A force of 10 Newton act on it in a direction making and angle of 60 degree with the x-axis. If it is displaced along the x-axis by 4 meter ,the work done by force is ?

Formula

Work done = Force * displacement cos@

or

w = FScos@

Solutions

Given

mass of body = 5kg

Force = 10N

displacement = 4m

the component of force along X- axis = Fcos60°

displacement is in X - axis so work done by body in y - axis is 0

Now work done by body in X - axis = 4*10cos60° = 4*10/2 = 20joule along X - axis

Answer 2

Solution :

⏭ Given:

✏ Mass of body = 5kg

✏ Displacement of body = 4m

✏ Force = 10N

✏ Angle between force and displacement = 60°

⏭ To Find:

✏ Work done by force

⏭ Formula:

✏ Formula of work done in terms of force and displacent is given by

• W = Fd cosβ

⏭ Terms indication:

• W denotes work done by force
• F denotes force
• d denotes displacement
• β denotes angle between force and displacement

⏭ Calculation:

✏ W = 10 × 4 × cos60°

✏ W = 40 × 1/2

✏ Work done by force = 20J

⏭ Additional information:

• Work done is scalar quantity.
• Force is vector quantity.
• Displacement is vector quantity.