Question

2. A body of mass 5kg moving along a su
line is accelerated from 4ms' to 8ms with
plication of a force of 10N in the same
direction. Then,
1) Work done by the force is 120J
2) Displacement of the body is 12m
3) Time for the change in velocity is 2s
4) All the above​

Answer 1

Answer:

Explanation: M = 5kg, F = 10N, U = 4ms, V = 8ms

F = MA

A = F/M = 10/5 = 2 ms

V2-U2 = 2AS

64 - 16/ 2*2 = S

48/4 = S

12 = S

W = F*S

W = 10*12

W = 120 J