Question

2. A body starts from rest with uniform acceleration and acquires a velocity V in time T. The instantaneous
kinetic energy of the body after any time t is proportional to:
(A) (VT)
(B)(V2/T)t2
(C)(V2/T2)
(D) (V2/T2)t2
7 .pand E denote the velocity, momentum and kinetic energy of the particle, then:​

Answer 1

Answer:

Explanation:

Here,

V = 0 + aT

=> a = V/T

So, at any time ‘t’ the velocity is,

v = 0 + at

=> v = (V/T)t

So, KE of the body after time t is,

KE = ½ mv2

=> KE = ½ m[(V/T)t]2

We know, work done is equal to gain in KE

So, Work done = ½ m[(V/T)t]2

Thus, work done is proportional to [(V/T)t]2.