Physics, asked by lipu6847, 2 months ago

2 A body travels from A to B at 25 m/s and from B to
A at 50 m/s, then its average speed will be
(a) o
(b) 37.5 m/s
(c) 16.3 m/s
(d) 33.3 m/s​

Answers

Answered by kjayesh661
9

Answer:

33.33

Explanation:

h

2xy/x+y=2*25*50/25+50=50*50/75=1/3=33.33

Answered by Blossomfairy
61

Given :

  • Initial velocity, u = 25 m/s
  • Final velocity, v = 50 m/s

To find :

  • Average velocity

According to the question,

 \sf :  \implies{Average  \: velocity =  \dfrac{ Initial \: velocity+ Final \: velocity }{2} }

 \\

 \sf :  \implies{ Average   \: _{velocity} =  \dfrac{25 + 50}{2} }

 \\

 \sf :  \implies{ Average   \: _{velocity} =  \dfrac{75}{2} }

 \\

 { \underline{ \boxed{\sf {\blue{:  \implies{ Average   \: _{velocity} =  37.5 \: m {s}^{ - 1} }}}}}} \:  \bigstar

 \therefore {\underline{ \sf {So, the  \: average  \: velocity \:  is \:  {37.5 \:  {ms}^{ - 1}  }}}}

Hence, option b) 37.5 m/s is correct.

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More formulas :

Newtons first equation of motion :

  • v = u + at

Newtons second equation of motion :

  • s = ut + ½ at²

Newtons third equation of motion :

  • v² = u² + 2as
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