Question

2. A body travels from rest and accelerates uniformly to a speed of 120km/h in 10 seconds
Calculate the distance covered​

Answer 1

Answer:

d=s/t

d=120/10d=12km

Answer 2

Explanation:

Initial velocity=u=0m/s

Final velocity(after 10 seconds of accelerating)=v=120km/hr

Thus,v=120 km/hr × 5/18=33.3 m/sec

acceleration=a=(v-u)/t

a=(33.3–0)/10=3.3 m/s ^2

Using one of the three kinematics equations,

s=ut+1/2at^2,

s=(0×10)+1/2×3.3×(10)^2

s=1/2×3.3×100

s=165m