Question

2. A body undergoes an acceleration of 10 ms
${}^{ - 2}$

starting from rest. Find the distance travelled by
it in 5 s.
Ans: 125 m ​

Answer 1

s=ut + 1/2 at^2

u=0

s= 1/2(10)(5×5)

s= 125m

Hope it helps you .......♡♡

Answer 2

Answer:

we use 2nd derivation of motion that is

S=ut+1/2 at^2

then S=0×5+1/2 10×5^2

S=0+125

S=125m