Question

2.A bomb is thrown in a horizontal direction with a velocity of 50 metres per second. It splits into two parts 6 kg and 3kg .The heavier fragment moves in the horizontal direction velocity of 40 metres per second calculate the velocity of the lighter fragment. ​

Answer 1

Answer:

Given,

Total Mass, M

total

=9kg

Initial velocity, V

initial

=50ms

−1

Lighter Mass =M

1

Final velocity of (M

2

=6kg)part, V

2

=80ms

−1

from conservation of momentum

Final momentum = initial momentum

M

2

V

2

+M

1

V

1

=M

total

V

initial

6×80+3×V

1

=9×50

V

1

=−10ms

−1

Final velocity of lighter mass is −10ms

Explanation:

tq follow me