Question

2.A boy read 2\3 of a book on the first day and 1\5 on the second day. On which day did he read major part of the book?​

Answer 1

Chemical reaction, a process in which one or more substances, the reactants, are converted to one or more different substances, the products. Substances are either chemical elements or compounds. A chemical reaction rearranges the constituent atoms of the reactants to create different substances as products.

Answer 2

Answer :

• Second day.

Given :

• 2/3 of a book on the first day.
• 1/5 on the second day.

To find :

• which day did he read a major part of the book?​

Solution :

⇒ Let's find on which day did he read a major part of the book.

$\longrightarrow \sf \dfrac{2}{3} \: and \: \dfrac{1}{5}$

• LCM of 3 and 5 = 15

$\longrightarrow \sf \dfrac{2 \times 5}{3 \times 5} \: = \dfrac{10}{15}$

$\sf \longrightarrow \dfrac{1 \times 3}{5 \times 3} = \dfrac{3}{15}$

• Therefore, the new fractions are 10/15 and 3/15.

⇒ Let's compare!

$\longmapsto \sf \dfrac{10}{15} \geq \dfrac{3}{15}$

$\longmapsto \sf \dfrac{2}{3} \geq \dfrac{1}{5}$

• Therefore, the boy reads a major part of the book on the second day.