Question

2)
A boy runs first 100 m with a uniform speed of 8 m/s & the next 200 m with a uniform
speed of 5 m/s. Calculate the average speed of the boy.
(Ans. 5.71 m/s]​

Answer 1

Answer:

$100 + 200 \div100 \div 8 + 200 \div 5$

5.71m/s

Answer 2

Answer:

5.71 m/s

Explanation:

first find time DATA V 1=8m/s ,s1=100m ,t1 =? t1=s1/v1=100/8= 12.5 sec DATA: v2=5m/s,s2= 200m t2=? t2 =200/5= 40 sec now Total time = t1+t2=12.5+40=52.5 sec total distance =200 +100= 300m Vavg=total distance /total time . Vavg =300/52.5=5.71m/s