Physics, asked by minijao72, 2 months ago

2. A bulb of power 100W is connected in a circuit of potential 300V.What will be the resistance of the bulb

Answers

Answered by operiostehpane20

0

290

Sana makatulong say

Answered by sonusagar50

2

Answer:900Ω

Explanation:

here given, p=100W and p.d(V)=300V we have to find R=?

R=V²/P=(300×300)/100=900Ω

HENCE,the resistance of the bulb is 900Ω

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