Question

2. A bulb of power 100W is connected in a circuit of potential 300V.What will be the resistance of the bulb​

Answer 1

290

Sana makatulong say

Answer 2

Answer:900Ω

Explanation:

here given, p=100W and p.d(V)=300V we have to find R=?

R=V²/P=(300×300)/100=900Ω

HENCE,the  resistance of the bulb​ is 900Ω