Question

2. A bullet moving with a velocity 100 m/s strikes amudwall and penetrates through 0.5 m. What is thetime of journey of the bullet through the mud wall?A) IsB)0.ISreolsD).02sE) 0.25​

Answer 1

Answer:

Initial velocity (u) = 100m/s

Final velocity (v) = 0

Distance (s) = 0.5m

Applying V^2-U^2=2as

0^2 - 100^2 = 2×a×0.5

10000 = 1a

a = 10000m/s^2

Applying V = u+at

V - U = at

0 - 100 = 10000×t

t = 100/10000

t = 0.01sec.