Physics, asked by sangitakol1233, 6 months ago

2. A bullet with a velocity u enters a wooden block and
gets retarded. After travelling a distance , the velocity
is reduced to v, and on penetration of a farther dis-
tance y, the bullet comes to rest. Show that,v/u=square root of y/x+y


I​

Answers

Answered by guptasant72
0

Answer:

hammer is a simple force amplifier that works by converting mechanical work into kinetic energy and back. In the swing that precedes each blow, the hammer head stores a certain amount of kinetic energy—equal to the length D of the swing times the force f produced by the muscles of the arm and by gravity.

Answered by thakurbkomal
0

Answer:

initial velocity =V

When bullet pennetrates 0.4m=

2

V

& let dist =x (when V

final

=0)

Applying, eq. of kinematic motion

4

V

2

=V

2

−2a(0.4) {a is de-acc a→(−)ve)

a=

4×0.8

3V

2

⟶(i)

Now, 0=

4

V

2

−2a(x)

2ax=

4

V

2

⟶(ii)

Putting (i) in (ii)

4×0.8

3V

2

a

=

8x

V

2

⇒x=

3

0.4m

x=

3

40

cm

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