Question

2. A bus at a uniform speed covers a distance of 140 2/3 km in 4 1/3 hours. Find the speed of the bus and
the distance covered in 6 1/2 hours.​

Answer 1

Avg. Speed of bus = total distance traveled / total time taken

total distance traveled = 140 2/3 = 422/3 = 140.667 km

total time taken = 4 1/3 = 13/3 =4.3333 hr

Avg. Speed of bus = 140.667 / 4.332 = 32.46 km/hr

Distance covered in 6 1/2 hours = 32.46 x 6.5 = 211 km

Answer 2

Answer:

● Sol : -

Distance = 422/3

Time = 13/3

so,

speed = distance/time

= 422/3/13/3 = 422/13 = 32 6/13

And

Distance = speed × Time = 422/13 × 13/2

= 211km