2. A bus has five stops. It carries 60 passengers. At the first stop, 15 get down.
At the second stop, 3 get down. At the third stop, half of the passengers get
down, while 10 more get down at the fourth stop. How many passengers will get
down at the last stop? ........
Answers
Answered by
4
Answer:
TOTAL 11 PASSAGERS WILL GET DOWN AT THE LAST STOP...
Answered by
5
Solution:
60 - 15 = 45 - First stop
45 - 3 = 42 - Second stop
42/2 = 21 - Third stop
21 - 10 = 11 - Fourth stop
Therefore, the passengers will get down at the last stop should be 11.
Hope this will be helpful.
60 - 15 = 45 - First stop
45 - 3 = 42 - Second stop
42/2 = 21 - Third stop
21 - 10 = 11 - Fourth stop
Therefore, the passengers will get down at the last stop should be 11.
Hope this will be helpful.
Similar questions