Question

2. A bus is moving at a speed of 20 m/s accelerates at the rate of 2 m/s. Then the distance
covered by the bus in 5 second is
​

Answer 1

Explanation:

s=ut+1/2at^2

=20×5+1/2×2×5×5

=100+25

=125m answer.

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Answer 2

Given:

• Initial velocity (u) = 20 m/s
• Acceleration (a) = 2 m/s²
• Time taken (t) = 5 sec.

To Find: Distance travelled in 5 seconds (s).

____...

We know,

s = ut + ½at²

where,

• s = Distance,
• u = Initial velocity,
• a = Acceleration and
• t = Time taken.

∴ s = (20 m/s)(5 s) + ½(2 m/s²)(5 s)²

→ s = 100 m + ½(2 m/s²)(25 s²)

→ s = 100 m + ½(50 m)

→ s = 100 m + 25 m

→ s = 125 m

∴ It covered 125 metres.