Question

2. A bus moves from Stop A to Stop B with a speed of 50 km/h travelling a distance 10 km. Then the driver
increases the speed upto 60 km/h. One of the passengers asks the driver to decrease the speed of the bus
because as per motor vehicle rule maximum speed limit for heavy vehicles is 40 km/h. After 6 minutes
moving with the speed of 60 km/h, it reaches Stop C. Then driver decreases the speed of the bus and reaches
Stop D, which is 12 km from Stop C.
Talue Based Questions
(a) Calculate the distance covered by the bus from Stop B to Stop C
(b) If the average speed of the bus is 40 km/h, what is the speed of the bus between Stop Cand Stop D?
(c) What value is shown by the passenger who asks the driver to decrease the speed of the bus?​

Answer 1

Answer:

A bus moves from stop A to stop B with a speed of 50km/hr travelling a distance 10km. then the driver increases the speed up to 60km/hr. one of the passengers asks the driver to decrease the speed of the bus because as per motor vehicle rule maximum speed limit for heavy vehicles is 40km/hr.

Speed continues to be one of the major factors contributing to accidents on Australia’s roads

Even a small reduction in speed can greatly reduce the chance or severity of an accident

Improvements in car design, combined with road education campaigns, have resulted in fewer deaths on Australian roads since the 1970s

More than 4100 people are injured in speed-related incidents each year in Australia

A car travelling at 65 km/h is twice as likely to be involved in a crash as a car travelling at 60 kilometres per hour

Answer 2

Answer:

a) 6 km

b) 30 km/hr

c) Compliance and consideration

Step-by-step explanation:

a) From Stop B to Stop C;

Speed = 60 km/h

Time = 6 min = 6/60 = 0.1 hr

Hence, Distance = Speed x Time

                            = 60 x 0.1

                            = 6 km

b) From Stop A to Stop B;

Distance = 10 km

Speed = 50 km/h

Time = 10/50 = 1/5 h

From Stop B to Stop C;

Distance = 6 km

Time = 6 min = 1/10 h

From Stop C to Stop D;

Distance = 12 km

Speed = x km/h

Time = 12/x

Therefore, Average speed = Total distance/Total time

40 = 10 + 6 +12 / 1/5 + 1/10 + 12/x

40 = 28 / (2x + 10x + 120/10x)

40 = 280x / 3x + 120

120x + 4800 = 280x

280x - 120x = 4800

160x = 4800

x = 4800/160

x = 30 km/h

Hence, the speed between Stop C to Stop D is 30 km/h

c) The values shown by the passenger are compliance and heeds for everyone's well-being.

Hope it helps...