2: A bus running at a speed of 18 km/h is
stopped in 2.5 seconds by applying brakes.
Calculate the retardation produced.
1 m/s2
2 m/s2
3 m/s2
4 m/s2
Answers
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Explanation:
Aneesh
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Aneesh 08:35
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Om T 08:35
A bus running at a speed of 18 km/h is
stopped in 2.5 seconds by applying brakes.
Calculate the retardation produced.
1 m/s2
2 m/s2
3 m/s2
4 m/s2
Aneesh 08:35
May I know in which topic you have a doubt?
Om T 08:35
A bus running at a speed of 18 km/h is
stopped in
Initial velocity, u=18 km/h
u=18×
3600
1000
=
3600
18000
m/s=5m/s
Final velocity, v=0 m/s
Time, t=2.5 sec
Acceleration, a=?
Using, v=u+at
a=
t
v−u
=
2.5
0.5
=−2m/s
2
So, retardation is 2m/s
2
..
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