Science, asked by vinitaawasthi46, 5 months ago

2: A bus running at a speed of 18 km/h is
stopped in 2.5 seconds by applying brakes.
Calculate the retardation produced.
1 m/s2
2 m/s2
3 m/s2
4 m/s2​

Answers

Answered by wamanraju002
1

Explanation:

Aneesh

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Aneesh 08:35

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Om T 08:35

A bus running at a speed of 18 km/h is

stopped in 2.5 seconds by applying brakes.

Calculate the retardation produced.

1 m/s2

2 m/s2

3 m/s2

4 m/s2

Aneesh 08:35

May I know in which topic you have a doubt?

Om T 08:35

A bus running at a speed of 18 km/h is

stopped in

Initial velocity, u=18 km/h

u=18×

3600

1000

=

3600

18000

m/s=5m/s

Final velocity, v=0 m/s

Time, t=2.5 sec

Acceleration, a=?

Using, v=u+at

a=

t

v−u

=

2.5

0.5

=−2m/s

2

So, retardation is 2m/s

2

..

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