Question

2.A bus starting from rest moves with a acceleration of 0.1 m/s2 for 2 min. Find
A) the speed acquired.
B) the distance travelled.​

Answer 1

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$\huge\bold\pink\bigstar{Answer}$

u = 0,      a = 0.1 m/sec²        t = 120 sec = 2minutes

equation of motion :  v = u + a t = 0 + 0.10 * 120 = 12 m/sec

s = u t + 1/2 a t² = 0 + 1/2 * 0.10 * 120² = 720 meters

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Answer 2

$\checkmark$ Given:

A bus starting from rest moves with a acceleration of 0.1 m/s² for 2 min

$\checkmark$ To Find:

• the speed acquired
• the distance travelled

$\checkmark$ Solution:

We know that,

$\red{\bigstar \ \boxed{\rm v=u+at}}$

Here,

• v = final velocity
• u = initial velocity
• a = acceleration
• t = time

According to the question,

We are asked to find the speed acquired

So, we must find "v"

Given that,

A bus starting from rest moves with a acceleration of 0.1 m/s² for 2 min

Hence,

• a = 0.1 m/s²
• t = 2 min = 120 sec
• u = 0 m/s [starts from rest]

Substituting the values,

We get,

$\blue{\rm \implies v=0+(0.1 \times 120) \ m/s}$

$\green{\rm \implies v=0.1 \times 120 \ m/s}$

$\red{\rm \implies v=12 \ m/s}$

Therefore,

$\star$ Speed acquired = 12 m/s

We know that,

$\pink{\bigstar \ \boxed{\rm s=ut+\dfrac{1}{2}at^{2}}}$

Here,

• s = distance
• u = initial distance
• t = time
• a = acceleration

According to the question,

We are asked to find the distance travelled

So, must find "s"

Given that,

A bus starting from rest moves with a acceleration of 0.1 m/s² for 2 min

Hence,

• a = 0.1 m/s²
• t = 2 min = 120 sec
• u = 0 m/s [starts from rest]

Substituting the values,

We get,

$\blue{\rm \implies s=0(120)+\dfrac{1}{2} \times 0.1 \times (120)^{2} \ m}$

$\green{\rm \implies s= \dfrac{1}{2} \times 0.1 \times (120)^{2} \ m}$

On further simplification,

We get,

$\pink{\rm \implies s=720 \ m}$

Therefore,

$\star$ Distance travelled = 720 m