Question

2.A bus starting from rest moves with a uniform acceleration of 0.1ms^ -2 for 2
minutes.Find
a) the speed acquired
b)the distance travelled

Answer 1

Explanation:

$u = 0 \\ v = ... \\ a = 0.1m {s}^{ - 2} \\ t = 2 \: minute = 2 \times 60 = 120 s \\ \\ v = u + at \\ \\ v = 0 + 0.1 \times 120 \\ \\ v = 12m {s}^{ - 1} ....answer(1) \\ \\ s = ut + \frac{1}{2} a {t}^{2} \\ \\ s = 0 + \frac{1}{2} \times 0.1 \times 120 \times 120 \\ \\ s = 0 + 720m \\ \\ s = 720m....answer(2)$

Answer 2

Answer:

Explanation:

Solution,

Here, we have

Initial velocity, u = 0

Acceleration, a = 0.1 m/s²

Time taken, t = 2 min = 2 × 60 = 120 seconds

To Find,

a. Speed acquired, v = ?

b. Distance traveled, s = ?

a. a. Speed acquired, v,

According to 1st equation of motion,

we know that,

v = u + at

⇒ v = 0 + 0.1 × 120

⇒ v = 0.1 × 120

⇒ v = 12 m/s

Hence, the speed acquired by bus is 12 m/s.

Now, Distance traveled, s,

According to 3rd equation of motion,

v² - u² = 2as

⇒ (12)² - (0)² = 2 × 0.1 × s

⇒ 144 = 0.2 × s

⇒ 144/0.2 = s

⇒ s = 720 m

Hence, the distance traveled by bus is 720 m.