Question

2. A bus starting from rest moves with a uniform acceleration of 0.1m/s2 for 2 minutes. Find the speed acquired and the distance travelled.

Answer 1

Given,
Initial velocity(u)="0m/s"

Accelaration(a)="0,1m/s-2"

Time="2 mins=60*2=120 secs"

Final velocity=?


v=u+at

v=0+(0.1)120

v=0+12

v=12m/s

i.e 

Final Velocity="12m/s"

Distance(s)=v(v)-u(u)=2a

s=144-0=2(0.1)

s=144=0.2


s=1440=2

s=720m 

Therefore,

(a)=12m/s

(b)=720m

Answer 2

Answer:

Initial speed of the bus, u= 0 m/s

Acceleration, a = 0.1 m/s2

Time taken, t = 2 minutes = 120 s

(a) v= u + at

v= 0 + 0×1 × 120

v= 12 ms-1

(b) According to the third equation of motion, v2 - u2= 2as

s is the distance covered by the bus

(12)2 - (0)2= 2(0.1) s

s = 720 m

Speed acquired finally by the bus is 12 m/s.

Distance travelled by the bus is 720 m.