Question

2. A car is travelling with a speed of 36km/h. The driver applied the brakes and retards the
the car uniformly. The car is stopped in 5sec. Find acceleration of car and distance before it
stops after applying brakes.​

Answer 1

Given

• Vi = 36 km/h = 10 m/s
• Vf = 0
• Time taken = t = 5 sec
• Acceleration =?
• Distance covered = S =?

For acceleration

a = v/t

a = 10 /5

Acceleration = 2 m/s^2

And

For distance we have,

S = Vit + 1/2 ( at^2)

S = 10 × 5 + 1/2 ( 2×5^2)

S = 50 + 1/2 (50)

S = 50 + 25

Distance = 75 meters

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