Question

2. A car of mass 1000 kg moving at a speed 10 m/s is brought to rest in 40 s. Find the

magnitude of the force applied?​

Answer 1

Answer:

Mass of car ( m ) =1000kg

Initial velocity ( u ) = 10m/s

Fimal velocity ( v ) = 0m/s

Time taken ( t ) = 40 seconds

Using eq. of motion

v = u + at

0 = 10 + a × 40

0 = 10 + 40a

-10 = 40a

-10/40 = a

-0.25 = a

acceleration = -0.25

Force = Mass × Acceleration

Force = 1000 × 0.25

Force = 250 newton.

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