Question

2. A car starts from rest and attains a velocity of 60m/s in 30s. If the acceleration is uniform, what is the distance travelled by the car to achieve this velocity?i will mark you brainliest​

Answer 1

Given

Car starts from rest.

Final velocity = 60 m/s

Time = 30 s

To find

Distance travelled by car.

Solution

As the car starts from rest,

➝ Initial velocity (u) = 0 m/s

We know equation of motion :

➺ a = (v - u)/t

➺ a = (60 - 0)/30

➺ a = 60/30

➺ a = 2 m/s²

We also know equation of motion :

➝ s = ut + ½at²

➝ s = 0t + ½(2 × 30²)

➝ s = 0 + ½(2 × 900)

➝ s = ½(1800)

➝ s = 900 m

Therefore,

Distance travelled by car = 900 m.

Solution 2 :

We know equation of motion :

⇒ v² - u² = 2as

Putting values we get :

⇒ 60² - 0² = 2 × 2 × s

⇒ 3600 - 0 = 4s

⇒ 4s = 3600

⇒ s = 3600/4

⇒ s = 900 m

Hence,

Distance travelled by car is 900 m.

Answer 2

Given:

A car starts from rest and attains a velocity of 60m/s

in time 30s

To Find:

The distance travelled by the car

Here,

Intial velocity U=0m/s

Time (t)=30m/s

Final velocity(v)=60m/s

• Using formula here

==>a=(v-u)/t

==>a=(60-0)/30

==>a=60/30

==>a=2m/s²

• again using formula to calculate distance

==>s=ut+1/2at²

==>s=0×t+1/2×2×30²

==>s=0+900

==>s=900m

Hence,

The distance travelled by car is 900m