2
A car travels from stop A to stop B with a speed of 30 km/h and then returns back to A with a
speed of 50 km/h. Find
(i) displacement of the car.
(ii) distance travelled by the car.
(iii) average speed of the car.
Answers
Answered by
1
Answer:
Time taken by the car when it moves from A to B is given by
t1 = Distance/Speed = x/30
Time taken by the car when it moves from B to A,
t2 = Distance/Speed = x/50
Total distance = 2x
Total time
= t1 + t2
= x/30 + x/50
= (5x + 3x)/150
= 8x/150
So, Average speed
= Total distance/Total time
= 2x/(8x/150)
= 37.5 km/hr
Similar questions