2- A car under constant
acceleration of 30m/s
2 has an
initial velocity of 10m/s. What will
be the displacement of the car at
the end of 5 seconds.
Answers
Answered by
12
Answer:
425 metres
Explanation:
Given :
- Initial velocity = u = 10 m/s
- Acceleration of the car = a = 30 m/s²
- Time taken = t = 5 seconds
To find :
- Displacement of the car at the end of 5 seconds = s
Using the first equation of motion :
V=u+at
V=10+30×5
V=10+150
V=160 m/s
Using the third equation of motion :
V²-u²=2as
160²-10²=2×30×s
25600-100=60s
25500=60s
s = 2550/6
S = 425 metres
The Displacement of the car at the end of 5 seconds is equal to 425 metres
Answered by
7
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