Question

2. A car was bought in current 2015
for 3,00,000. If the value of the car
depreciates by 5% each year, find its
worth in the year 2018.
​

Answer 1

SOLUTION:-

☛Worth of car in 2016 =

$300000 \times ( \frac{5}{100} )$

$= Rs.285000$

☛Worth of car in 2017 =

$285000 - 285000 \times ( \frac{5}{100} )$

$= Rs. 270750$

☛ Wort of car in 2018

$270750 - 270750( \frac{5}{100} )$

${ \boxed{ \red{ \bf{= Rs. 255000}}}}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:{ \bf{ or}}$

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${ \bf{ \underline{Given:-}}}$

• P= 300000
• r = 5
• n = 3

${ \bf{ \underline{Solution:-}}}$

By applying formulae,

${ \mathtt{ \green{a = p \times (1 - \frac{r}{100} }{ \green{)}}^{n}}}$

where,

${ \mathtt{ \pink{a = final \: value \: of \: n \: year}}}$

${ \mathtt{ \pink{p = initial \: value}}}$

${ \mathtt{ \pink {r = rate \: of \: depreciation}}}$

By putting the given values in the formulae, we get

$a = 300000 \times (1 - { \frac{5}{100} })^{3}$

$= 300000 \times ( \frac{19}{20} ) \times ( \frac{19}{20} ) \times ( \frac{19}{20}$

${ \boxed { \bf{ \red{Rs.255000}}}}$

☛So worth of car in year 2018 is Rs.

2,55,000

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