Question

2) A cell is connected to a 9 ohm resistance, because of which heat and 400J is produced per second due to current flowing through it. Obtain the potential difference applied across the resistance.​

Answer 1

Answer:

60 Volt

Explanation:

here, H = 400 J

R = 9 ohm

t = 1 s

v = potential difference

we know,

from joule's law

$h = \frac{ {v}^{2} t}{r}$

$=> 400 = \frac{ {v}^{2} \times 1}{9}$

$=> {v}^{2} = 400 \times 9$

$=> v = \sqrt{400 \times 9}$

$=> v = 20 \times 3$

$=> v = 60$

so, the potential difference is 60 V

Answer 2

The potential difference applied across the resistance is 60 volts.

Explanation:

It is given that,

Resistance of the cell, R = 9 ohms

Heat energy produced, H = 400 J

The heat produced by the electrical appliance is given by :

$H=I^2Rt$

Since, V = IR

$H=\dfrac{V^2t}{R}$

t = 1 s

$V=\sqrt{\dfrac{HR}{t}}$

$V=\sqrt{\dfrac{400\times 9}{1}}$

V = 60 volts

So, the potential difference applied across the resistance is 60 volts. Hence, this is the required solution.

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