2. A certain sum of money becomes
*2250 at the end of 2 yr and
becomes 2625 at the end of 5 yr.
If the person receives only simple
interest, then the rate of interest is in short trick
Answers
Answer:
don't know the answer
Step-by-step explanation:
Given:-
A certain sum of money becomes Rs.2250 at the end of 2 years and becomes Rs. 2625 at the end of 5 years .
To find:-
If the person receives only simple interest, then Find the rate of interest ?
Solution:-
Short cut:-
Let the rate of interest be R %
First amount = Rs .2520 in 2 years
A1 = Rs. 2520
t1 = 2 years
Second amount = Rs. 2625 in 5 years
A2 = Rs. 2625
t2 = 5 years
If a sum amounts to Rs. A1 in t1 years and Rs. A2 in t2 years at simple interest then Rate of interest per annum is [100(A2-A1)] / (A1t2-A2t1)
=>R = [100(2625-2250)] / [(2250×5)-(2625×2)]
=>R = 100(375)/(11250-5250)
= R = 37500/6000
=>R=375/60
=>R= 75/12
=>R = 6.25%
Rate of interest = 6.25%
General method:-
Let the sum be Rs. P
Let the rate of interest be R%
Amount (A)=Rs.2250
Time (T)=2 years
we know that
I = PTR/100
A = P+I
=>A = P+(PTR/100)
=>P+(P×2×R/100)=2250
=>P+(2PR/100)=2250
=>(100P+2PR)/100 = 2250
=>(50P+PR)/50 = 2250
=>50P+PR = 2250×50
=>50P +PR =112500--------(1)
Sum =Rs. P
Time (T)=5 years
Amount (A)=Rs. 2625
A = P+(PTR/100)
=>P+(P×5×R)/100=2625
=>P+(5PR)/100=2625
=>P+(PR/20)=2625
=>(20P+PR)/20 = 2625
=>20P+PR = 2625×20
=>20P+PR = 52500--------(2)
On subtracting (2) from (1) then
.
50P +PR =112500
20P+PR = 52500
(-)
_______________
30P +0 = 60000
________________
=>30 P = 60000
=>P = 60000/30
=>P = Rs. 2000
The sum is Rs. 2000
Now on Substituting the value of P in (2) then
20(2000)+2000R = 52500
=>40000+2000R = 52500
=>2000R = 52500-40000
=>2000R = 12500
=>R = 12500/2000
=>R = 125/20
=>R = 6.25%
Rate of interest = 6.25%
.
Answer:-
The rate of interest for the given problem is 6.25%
Used formulae:-
- Simple Interest (I)=PTR/100
- Amount = Principle+ Interest
- If a sum amounts to Rs. A1 in t1 years and Rs. A2 in t2 years at simple interest then Rate of interest per annum is
- [100(A2-A1) ]/ (A1t2-A2t1)