Question

2. A charge of 5000C flows through a conductor for 2 hours and 30 minutes. Find the magnitude of current flowing through the conductoe​

Answer 1

Explanation:

Given that,

Charge = 5000 C.

Time = 2.5 hours = 2.5 = 9000 sec.

To find,

The current flowing.

Solution,

We know that,

Current= \frac{Charge }{time}Current=timeCharge

⇒ \frac{5000}{9000} = \frac{5}{9}= 0.55 \ A90005000=95=0.55 A

Therefore the current flowing is 0.55