2. A charge Q is uniformly distributed over a rod of length
1. Consider a hypothetical cube of edge l with the centre
of the cube at one end of the rod. Find the minimum
possible flux of the electric field through the entire
surface of the cube.
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Answer:
Hey mate here is your answer.//
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Explanation:
Here, half of the length of the rod outside the cube. From Gauss's law, flux,ϕ=Qen/ϵ0,
Out side cube=l/2,
where Q en ,
=charge inside the cube= Q/2,
thus, flux(ϕ)=Q/2ϵ0.
Hope it helps you.//✔✔✔
Please do mark me as Brainliest.//
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