Question

(2) A circle with centre 0, OM congruent AB, ON congruentCD
OM = ON = 3.9 cm and AB = 8.6 cm.
Find I(CD).
with diagram​

Answer 1

Answer:

Given : AB = 24 cm, OM = 5 cm, ON =12 cm

OM⊥AB

M is the midpoint of AB

AM=12cm

(i) Radius of circle OA=

OM

2

+AM

2

OA=

5

2

+12

2

=

25+144

=

169

=13

(ii) Again OC

2

=ON

2

+CN

2

∵OC=OA

13

2

=12

2

+CN

2

CN=

13

2

−12

2

=

169−144

=

25

CN=5cm

As ON⊥CD, N is the mis-point of CD

CD=2CN=2×5=10 cm