(2) A circle with centre 0, OM congruent AB, ON congruentCD
OM = ON = 3.9 cm and AB = 8.6 cm.
Find I(CD).
with diagram
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Answer:
Given : AB = 24 cm, OM = 5 cm, ON =12 cm
OM⊥AB
M is the midpoint of AB
AM=12cm
(i) Radius of circle OA=
OM
2
+AM
2
OA=
5
2
+12
2
=
25+144
=
169
=13
(ii) Again OC
2
=ON
2
+CN
2
∵OC=OA
13
2
=12
2
+CN
2
CN=
13
2
−12
2
=
169−144
=
25
CN=5cm
As ON⊥CD, N is the mis-point of CD
CD=2CN=2×5=10 cm
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