Question

2) A circle with centre o in which diameter
AB bisects the chord CD at point E. If
CE = ED = 8 cm and EB = 4cm, find the
radius of the circle.
3.0 Marks
a. 12 cm
b. 10 cm
c. 11 cm
d. none of the above​

Answer 1

Answer:

a.

Explanation:

12cm

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Answer 2

Answer:

consider the above figure .

let OE= xcm and Let oc= radius of the circle = acm

in OCE, applying paythagoras theorem we have

OE²+CE²= a²

X²+8²= a²........(1)

also we have ,OE+EB= OB= radius of the circle = a

x+4= a

(x+4)²= a².......(2)

from equation (1) and (2) we have

x²+8²= (x+4)²

x²+64= x²+16+8x

64= 16+8x

16+8x= 64

8x= 64-16

8x= 48

x= 48/8 = 6

Thus the, radius of the circle is a = x+4= 6+4=10cm