Question

2. A concave mirror magnifies images by a factor of 2.6. a. What is the height of an image formed by a 0.89 m tall object? b. What is the height of an object that has a 1.8m tall image? c. What is the object distance of an image that has a position of -2.00m?

Answer 1

Answer:ho= 0.34m

Explanation

(a) magnification (M) = hi/ho

M=2.6

hi= 0.89m,

ho=hi/M

ho= 0.89m/2.6 = 0.34m.

(b)

ho= 6.9m

Solution

ho = hi/M

ho= 18m/2.6= 6.9m

(C) u= 0.77m

M=v/u

u = v/M= 2m/2.6

u = 0.77m