Question

2. A cricket ball is thrown at a speed of om sin a direction 300 above the horizontal, such that the
maximum height is 10 m. Then the value of vois
(a) 69 ms
(b) 14 ms
(c) 28 ms
(d) 56 ms​

Answer 1

Answer:

69

Explanation:

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Answer 2

Answer:

Explanation:

Given :   u=28 m/s          θ=30o

(a) :  Maximum height   H=u2sin2θ​/2g

⟹ H=282/2×9.8×0.52​=10 m

(b) :  Time of flight   T=2usinθ/​g

⟹ T=2×28×sin30/9.8​=2.86 s

(c) :  Range    R=ucosθ×T

⟹ R=28×cos30o×2.86=69.27 m